x+1x=2 x+ \frac1x = 2 x+x1=2ആയാൽ x2+1x2 x^2 + \frac1 {x^2}x2+x21 = __ A2B4C1D6Answer: A. 2 Read Explanation: x+1x=2 x+ \frac1x = 2 x+x1=2 [x+1x]2 [x + \frac1x]^2 [x+x1]2= x2+2×x×1x+1x2x^2+2 \times x \times \frac1x + {\frac1x}^2x2+2×x×x1+x12 = 4 x2+2+1x2x^2+2 + \frac1x^2x2+2+x12 = 4 x2+1x2 x^2 + \frac1 {x^2}x2+x21 = 4 - 2 = 2 Read more in App